Oblique projectile motion (Left), Horizontal projectile motion (Middle), Projectile motion on an inclined plane (Right)
Kinematic quantities of projectile motion                             The magnitude of the displacement:
Where,                                                                 r     x2  y2
X axis is horizontal and Y axis is vertical.                          The maximum height of projectile
sin θ is the component along y-axis                                         v 0 2 sin2 ()
cos θ is the component along x-axis
                                                                      Circular Motion
V0 is the initial Velocity,
                                                                           It is a movement of an object along the
Vx is the velocity along x-axis                                             circumference of a circle or rotation along
                                                                            a circular path.
Vy is the velocity along y-axis
                                                                           It can be uniform, with constant angular
g is the acceleration due to gravity and                                    rate of rotation and constant speed, or non-
                                                                            uniform with a changing rate of rotation.
t is the time taken.
                                                                           Examples of circular motion include: an
                                                                            artificial satellite orbiting the Earth at
                                                                            constant height, a stone which is tied to a
 ax  0
                                                                            rope and is being swung in circles.
 ay   g
                                                                      Velocity in Circular Motion:
Velocity                                                                    d
                                                                       v r       r
 v x  v 0 cos()
 v y  v 0 sin( )  gt                                               Acceleration in Circular Motion:
The magnitude of the velocity                                                d          v2
                                                                      av          v
                                                                             dt            r
 v  vx 2  vy 2
                                                                      Where the angular rate of rotation is ω. (By
                                                                      rearrangement, ω = v/r.) Thus, v is a constant,
Displacement                                                          and the velocity vector v also rotates with
                                                                      constant magnitude b, at the same angular rate
At any time t, the projectile"s horizontal and                        ω.
vertical displacement:
 x  v 0 t cos( )
 y  v 0 t sin( )  gt 2